Given: Prove:ΔAMD≅ΔBMD

A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.

AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)

ABMC is half AABC. ABMD is half ABMC, so is 1/4 of AABC. (By the formula for area of a triangle.)

Then, AADC = 1/4 AABC = ABMC, so AADC = ABMC by the transitive property of equality.

Step-by-step explanation:

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%

the equation is not included but the answer is (1.50, 2.00, 2.75)

step-by-step explanation: