Mathematics, 20.10.2021 01:00 toomuch94

A company has $8,970 available per month for advertising. Newspaper ads cost $200 each and can't run more than 19 times per month. Radio ads cost $470 each and can't run more than 28 times per

month at this price.

Each newspaper ad reaches 5800 potential customers, and each radio ad reaches 7100 potential

customers. The company wants to maximize the number of ad exposures to potential customers.

Use n for number of Newspaper advertisements and r for number of Radio advertisements.

Maximize P =

subject to

< 19

< 28

< $8,970

Enter the solution below. If needed, round ads to 1 decimal palace and group exposure to the

nearest whole person.

Number of Newspaper ads to run is

Number of Radio ads to run is

Maximum target group exposure is

people

Answers: 3

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A company has $8,970 available per month for advertising. Newspaper ads cost $200 each and can't r...