$D$ is on side $\overline {AB}$ of $\triangle ABC.$ We know $\triangle ABC \sim \triangle ACD$ and we know all the marked side lengths. [asy] size(5cm); pair A, B,C, D; A=(0,0); B=(4,0); C=2*dir(48); D=foot(C, A,B) + (-0.3,0); draw(C--A--B--C--D); label("$A$",A, SW); label("$B$",B, SE); label("$C$",C, N); label("$D$",D, S); label("$3$", A--D, S); label("$6$", A--C, W); [/asy] What is the length $AB?$

∞ this is your sign

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

answer: (1,3) (3,-1) (5,-5) ?

step-by-step explanation:

the functions have the same rate of change i think. i narrowed it down to this answer and "the rate of change of tour 1 is greater" but i got it wrong using that answer so im assuming its the answer above. (this is a question i also answered from the iready site if anyone needs a reference)