Given a square ABCD with side length equal to 'a'. From side AB, draw a line extending from point B in the opposite direction of point A, and place point B1 on the line continuing from side AB where AB1 = AC. Use the concatenated side BB1 to create a square BB1C1D1. Then, from side BB1, draw a line extending from point B1 in the opposite direction of point B, and place point B2 on the line connecting from this side BB1, where BB2 = BC1. Given point B1, B2, B3, ... As described above, find the sum of the lengths of the line segments AB, BB1, B1B2, ... Please show your work too — thanks!
Topic: Infinite Geometric Series

Step-by-step explanation:

AB = a - given

BB₁ is the difference of the diagonal and side of the square with side a:

Each subsequent line segment is times the previous.

So we have a GP with the first term of a and common ratio of .

The sum of the lengths is the sum of infinite GP:

So the sum is:

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !

answer: what are the following choices