(2m2+10m+1) from (−8m2−8m+12)

4mfro• (2m2+10m+1)•(2m2+2m-3)

STEP

1

:

Equation at the end of step 1

0-2•(m2))+10m)+1)•f)•r)•o)•m)•(((0-23m2)-8m)+12))

STEP

2

:

Equation at the end of step

2

:

0-2m2+10m)+1)•f)•r)•o)•m)•(-8m2-8m+12))

STEP

3

:

Trying to factor by splitting the middle term

3.1 Factoring 2m2+10m+1

The first term is, 2m2 its coefficient is 2 .

The middle term is, +10m its coefficient is 10 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 2 • 1 = 2

Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is 10 .

-2 + -1 = -3

-1 + -2 = -3

1 + 2 = 3

2 + 1 = 3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

3

:

0-f•(2m2+10m+1)•r)•o)•m)•(-8m2-8m+12))

STEP

4

:

Equation at the end of step 4

0-(((fr•(2m2+10m+1)•o)•m)•(-8m2-8m+12))

STEP

5

:

Equation at the end of step 5

0-((fro•(2m2+10m+1)•m)•(-8m2-8m+12))

STEP

6

:

Equation at the end of step 6

0 - (mfro • (2m2 + 10m + 1) • (-8m2 - 8m + 12))

STEP

7

:

STEP

8

:

Pulling out like terms

8.1 Pull out like factors :

-8m2 - 8m + 12 = -4 • (2m2 + 2m - 3)

Trying to factor by splitting the middle term

8.2 Factoring 2m2 + 2m - 3

The first term is, 2m2 its coefficient is 2 .

The middle term is, +2m its coefficient is 2 .

The last term, "the constant", is -3

Step-1 : Multiply the coefficient of the first term by the constant 2 • -3 = -6

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is 2 .

-6 + 1 = -5

-3 + 2 = -1

-2 + 3 = 1

-1 + 6 = 5

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

8

:

0 - -4mfro • (2m2 + 10m + 1) • (2m2 + 2m - 3)

STEP

9

:

Final result :

4mfro • (2m2 + 10m + 1) • (2m2 + 2m - 3)

one that is bigger than 3 1/2

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.