10=0+15 =87+99=))-5436*985

free ponit

The weights of players in a basketball league are distributed normally. the distance (d) of each player's weight (w) from the mean of 86 kilograms was computed as follows: d = |w - 86| if d is greater than 7 for approximately 5% of the players, what is the approximate standard deviation of the players' weights? a. 1.75 kilograms b. 3.5 kilograms c. 4.3 kilograms d. 7 kilograms

Given abcd ac=38 and ae=3x+4 find the value of x

50 points~ ! i have to turn this in tomarrow