Mathematics, 17.10.2021 14:00 faithtunison

For a>0, log a +log 3a^3 + log 5a^5= A)9 log 15a
B)log(9a^15)
C) log(a+3a^3+5a^5)
D)log 15+9log a

Answers: 1

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For a>0, log a +log 3a^3 + log 5a^5= A)9 log 15a
B)log(9a^15)
C) log(a+3a^3+5a^5)