Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of \$65$65dollar sign, 65 along with an hourly rate of \$28$28dollar sign, 28. The plumber only charges for a whole number of hours. Anand would like to spend no more than \$250$250dollar sign, 250, and he wonders how many hours of work he can afford. Let HHH represent the whole number of hours that the plumber works.
1) Which inequality describes this scenario?
Choose 1
Choose 1

(Choice A)
A
28+65H \leq 25028+65H≤25028, plus, 65, H, is less than or equal to, 250

(Choice B)
B
28+65H \geq 25028+65H≥25028, plus, 65, H, is greater than or equal to, 250

(Choice C)
C
65+28H \leq 25065+28H≤25065, plus, 28, H, is less than or equal to, 250

(Choice D)
D
65+28H \geq 25065+28H≥25065, plus, 28, H, is greater than or equal to, 250
2) What is the largest whole number of hours that Anand can afford?
hours

6hours of work? i kinda get the question but im not completely understanding

Step-by-step explanation:

65+28x

x is the number of hours he would pay for the plumber to work

x=6

65+28(6)                                       MULTIPLY

65+168                                          ADD

233

we cant go hirer than 250. /

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺

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