The perimeter of a rectangle is 28cm it’s length is more than 10cm more than it’s widith which equation can be used to find the dimensions

P = 2((10 + x) + x)

The perimeter of a rectangle is the sum of the length and width multiplied by 2

P = 2(l + w)

[to simplify the expression]

P = 2 × (l + w)

[using x to represent the width]

w = x

l = x + 10

P = 2 × ((10 + x) + x)

P = 2((10 + x) + x)

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680