Find intercepts of: 3x-3y+9=0
X-intercept as a ordered pair
Y-intercept as a ordered pairr

3x - 3y + 9 = 0

The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, b). It is also the value of y when x = 0.

To solve for the y-intercept, set x = 0:

3(0) - 3y + 9 = 0
3(0) - 3y + 9 = 0

Subtract 9 from both sides:
- 3y + 9 - 9 = 0 - 9
- 3y = -9
Divide both sides by -3 to solve for y:

-3y/-3 = -9/-3
y = 3

Therefore, the y-intercept is (0, 3).

The x-intercept is the point on the graph where it crosses the x-axis, and has coordinates of (a, 0). It is also the value of x when y = 0.

To solve for the x-intercept, set y = 0:

3x - 3(0)+ 9 = 0
3x -0 + 9 = 0

Subtract 9 from both sides:
3x + 9 - 9 = 0 - 9
3x = -9

Divide both sides by 3 to solve for x:

3x/3 = -9/3
x = -3

Therefore, the x-intercept is (-3,0).

The correct answers are:
Y-intercept = (0, 3)
X-intercept = (-3, 0)

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