I need someone to explain to me how to solve this, because I need to show my work.

So to find the answer you have to know what the mixture is, what the trend is,

on day one he used 4 cans of blue and 6 cans of yellow

day two, 6 blue and 9 yellow

both are divisible by 2 and 3 respectively, additionally when you divide the number of blue cans Marc used by the number of yellow cans each day you get a sum of .66

those are the trends

so therefore day three would have the same trend.

Now on day three Marc will have 4 cans of blue paint and 5 cans of yellow paint remaining, what I did here to find the answer was divide numbers under 4 and 5 until I got a division problem that equaled .66

my answer was 2 blue cans and 3 yellow.

The answer is that on day three the highest number of cans that Marc can mix to get his favorite shade of green is 2 blue and 3 yellow

300b(x) is graphed by the functio

Idon’t know how to do that