An SRS was conducted to find out how much television students watch on the weekend. Twenty-five students were selected and asked "How many hours of TV did you watch this weekend?" Their responses are listed below. What is the mean (p)? Do you expect that this mean is the same as the true population mean? Explain.

5, 4, 3, 7, 5, 2, 5, 4, 8, 3, 6, 6, 5, 4, 6, 7, 5, 5, 3, 4, 6, 5, 7, 6, 4

What kind of data is this, categorical or quantitative. quantitative

36% of students watch 6 or more hours of television. What is the margin of error for the sample of 25?

Calculate the 95% confidence interval for students who watch 6 or more hours of television?

Write the 95% confidence statement for the problem above..

details

step-by-step explanation:

range =5

step-by-step explanation:

to find the range, we take the largest value and subtract the smallest value.

the largest value is 5

the smallest value is 0

the range is 5-0   =5

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)

i think it’s c i believe