Write the equation of the line that passes through the points (
−
3
,
−
5
)
(−3,−5) and
(
3
,
1
)
(3,1). Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line.

y+2-x=0

Step-by-step explanation:

Here,

(-3,-5)=(x1,y1)

(3,1)=(x2,y2)

Slope(m)=y2-y1/x2-x1

=1-(-5)/3-(-3)

=1+5/3+3

=6/6

=1

Mid point=(x1+x2/2 , y1+y2/2)

=(-3+3/2 , -5+1/2)

=(0/2 , -4/2)

=(0 , -2)

Now, (0,-2)=(x1,y1)

Equation:

y-y1=m(x-x1)

y+2=1(x-0)

y+2=1x

y+2-x=0 is the required equation.

yes the data was not prsented

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: