In the given figure, AOB is a line. Determine the value of Angle BOD , Angle DOC and Angle COA.

From the given figure:

∠BOD = 2y°

∠DOC = 3y°

∠COA = 5y°

We know that

The sum of the angles lie on the same line = 180°

=> ∠BOD + ∠DOC + ∠COA = 180°

=> 2y° + 3y° + 5y° = 180°

=> 10y° = 180°

=> y° = 180°/10

=> y° = 18°

Therefore, y = 18°

From the given figure:

∠BOD = 2y°

∠DOC = 3y°

∠COA = 5y°

We know that

∠COA = 90°

=> 5y = 90°

=> y = 90°/5

=> y = 18°

From the given figure:

∠BOD = 2y°

∠DOC = 3y°

∠COA = 5y°

We know that

∠BOC+∠DOC = 90°

Since they are complementary angles

=> 2y+3y = 90°

=> 5y = 90°

=> y = 90°/5

=> y = 18°

Therefore, y = 18°

The value of y for the given problem is 18°

→ The sum of the angles lie on the same line = 180°

→ The sum of two angles is 90° then they are called Complementary angles.