Pleaseee help! Important. Brainliest to correct!

Step-by-step explanation:

If we look at the general equation of position in time with constant accelerations

s = s₀ + v₀t + ½at²

and compare to our equation

h = 5 + 20t + -16t²

we can see that ½a = -16, therefore gravity is -32 ft/s²

that gravity will reduce the initial velocity to zero in

t = v₀/g = 20/32 = 0.625 s

at that time the ball will be

h = 5 + 20(0.625) + -16(0.625)² = 11.25 ft above the ground.

We could also find the time of maximum height by realizing the velocity at that moment would be zero.

As the slope of the position/time chart is velocity at any instant, taking the derivative of our equation and setting it equal to zero gives us

20 - 32t = 0

t = 0.625 s

same result.

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e