DRAG & DROP THE ANSWER

62° for box above

118° for second box

Step-by-step explanation:

Since both lines are given parallel, we can apply theorems here.

For the first box above is 62°. This is alternate interior theorem where if both lines are parallel, both angles have same measure or are congruent.

For the second box, since we don't know what the second box's value is, we will leave it as x.

Therefore:-

62+x

Since 62+x forms a line; a line's measure is 180°.

Thus:-

62+x=180

x = 180-62

x = 118°

the answer to the question is a

step-by-step explanation:

it has the same slope and the same y-intercept.

y + 11 = -7/9(x - 18)

y + 11 =-7/9x + 14

b

y = -7/9x + 3

y-intercept (0, 3)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.