There are two numbers whose $400^{\text{th}}$ powers are equal to $9^{1000}$. In other words, there are two numbers that can replace $\blacksquare$ in the equation $$\blacksquare^{400} = 9^{1000},$$making the equation true.

Find the smaller of the two numbers.

± 243

Work:

x^400 = 9^1000

so the GCF of 400, 1000  = 200

(x^2)^200 = (9^5)^200

(x^2) = 9^5      

(x^2) = (3^2)^2

x^2  = 3^10    

x = ± √[3^10]  =   ± [ 3] ^(10/2)  =  ± [3]^5  =  ± 243

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation:

kayla would of sent 8

step-by-step explanation: