Given that x+4 is a factor of x^3+ax^2-29x+12

For factoring x

3

−6x

2

+3x+10, we should know atleast one zero of this polynomial. Once we know it, we can divide the polynomial by the factor to find the quotient and factor the quotient further to find other zeroes.

Keeping x=1,(1)

3

−6(1)

2

+3(1)+10



=0

⇒x=2,(2)

3

−6(2)

2

+3(2)+10=0

so, (x−2) is a factor.

Now,

⇒ Quotient =x

2

−4x−5

Using common factor theorem.,

x

2

+x−5x−5

x(x+1).5(x+1)

(x+1)(x−5)

To find zeroes (x+1)(x−5)=0

⇒x=−1,x=5

So, the zeroes of polynomial x=−1,2,5.

Hence, the answer should be (x+1)(x−2)(x−

a = - 4

Step-by-step explanation:

Assuming you require to find the value of a

Given (x + h) is a factor of f(x) then f(- h) = 0

Here f(x) = x³ + ax² - 29x + 12 and h = - 4 , then

(- 4)³ + a(- 4)² - 29(- 4) + 12 = 0

- 64 + 16a + 116 + 12 = 0

16a + 64 = 0 ( subtract 64 from both sides )

16a = - 64 ( divide both sides by 16 )

a = - 4

answer: the answer is 35%

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.