Lesson 4: Let ABC be a triangle. The three altitudes AD, BE, CF intersect at H. let I, J,K be the midpoints of HA, HB, HC respectively. Let M, N, P be the midpoints of AB, BC and CA respectively. Prove that: a) Four points M, P, K, J are on the same circle
B) Six points M, P, K, J, I, N are on the same circle
c) Nine points M, P, K, J, I, N, D, E, F are on the same circle

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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cant see photo

step-by-step explanation: