jane has a ton of 5p and 2p coins. if she takes 4 coins how many different totals could she have? i’ll pick brainiest to whoever gets it right :)

5

Step-by-step explanation:

Im not sure if this is correct but i think the question is asking forehow many combinations there can be. you can have 5555, 5552, 5522, 5222, or 2222.

that means 5 combinations.

however, if the order of numbers in the combinations matter, which i dont think it does, there can be many more combinations. 5555, 2555, 5255, 5525, 5552, 2255, 2525, 2552, 2252, 2522, 2222. i think thats all the combinations

this adds up to 11 combinations

i hope this helps. im sorry if it didnt

the mean and mad

step-by-step explanation:

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.