−x + y = 6
2x + y = −12

6, 12

-x+y=6    [eq.1]

2x + y = - 12    [eq.2]

    [eq.2] - [eq.1]

2x + y - (-x) - y = - 12 - 6

2x +x =-18

3x=18

x = 18/3

ans: x = 6

substituting x=6 in [eq.1]

-x + y = 6

-6 +y =6

ans: y= 12

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

add an image, and i will answer

step-by-step explanation: