Melanie buys 6 pounds of beef and 3 pounds of bacon. She pays a total of $63, and the bacon costs $1.50 less per pound than the beef. What would be the
combined cost of 1 pound of beef and 1 pound of bacon? *

Cost of 1 beef= $7.5

Cost of 1 bacon= $6

Step-by-step explanation:

Ok so first of organize everything:

We know she buys 6 pounds ->beef and 3 pounds ->bacon

First we need to set up an equation of how much 1 beef costs and 1 bacon costs:

Let’s say f=cost of 1 beef and b=cost of 1 bacon

Now lets make the equation:

6f+3b=63. (She buys 6 portions of beef and 3 bacon and her total comes out to 63)

Now their is another condition that the cost of one bacon is -$1.50 per pound than beef.

So we can say b=f-1.50

Do you notice anything similar? The b has a value now and so we can replace the b in our first equation with the b of the 2nd (b=b)

So hence,

6f+3(f-1.50)=63

6f+3f-4.5=63

9f=67.5

F=7.5 (This is the cost for 1 pound of beef)

Now lets find out for bacon,. Now instead of doing this equation all over again just insert it into the b=f-1.5 you know make life easier for yourself:

B=7.5-1.5

B=6

Cost of 1 beef= $7.5

Cost of 1 bacon= $6

is there answer choices?

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this