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Mathematics, 26.09.2021 02:10 scasemere

Solve the equation on the interval [0, 2π).
4(sin x)^2 - 2 = 0


Solve the equation on the interval [0, 2π). 4(sin x)^2 - 2 = 0

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Solve the equation on the interval [0, 2π).
4(sin x)^2 - 2 = 0
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