What is the equation of the line through (−2, −2) and (4, −5)? A. y = 12x – 1
B. y = –12x – 3
C. y = 2x + 2
D. y = –2x – 6

y = -1/2x - 3

Step-by-step explanation:

slope: (y2-y1) / (x2-x1)

(-5 - -2) / (4 - -2)

(-5 + 2) / (4 + 2)

-3 / 6

- 1 / 2

y-intercept: y = mx + b

-5 = -1/2(4) + b

-5 = -2 + b

-3 = b

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

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step-by-step explanation:

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