One pumpkin is launched from a height of 7 meters. The initial upward velocity of the pumpkin is 24 meters per second. The acceleration due to gravity (g) on the pumpkin is –9.8 meters per second squared. One equation for the height h (in meters) of the pumpkin at the time t seconds is: LaTeX: h\left(t\right)=\frac{1}{2}(acceler ation due to gravity)(LaTeX: t seconds)LaTeX: ^2+(velocity)(LaTeX: t seconds)LaTeX: +(initial height in meters)

answer: it would most likely be y=6 and 5/7.

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v