Find an equation of a line tagent to the circle x^2+(y-3)^2=34 at the point (5,0)

First, plot your circle. the Center is (0, 3) and the radius is

Now to find your slope move from the (0, 3) to (5, 0)

The slope of a perpendicular line is opposite and reciprocal, so the slope is

The equation of our line tangent to the circle at the point (5, 0) is

Now substitute in the point (5, 0) to solve for b

Therefore, the equation of the line tangent to the circle is

Step-by-step explanation:

a) 0.25x times 3. (could be wrong on equation.)

b) 2.25 pound of dark chocolate. (can i eat all the chocolate? plz? anyway, again, could be wrong, but i hope im right. all the chocolate together should be 5.25 pounds)

have a good day!

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: