Problem 3: Let Ω be a sample space, and P a probability on Ω. Suppose that B1, B2, B3 are pairwise disjoint, have positive probability, and their union is Ω. We let G := σ (B1, B2, B3) .
For a fixed set A ⊂ Ω, suppose that we have P(A|G) = 12IB2. Here, IB2 denotes the
indicator function of the set B2.
(a). Show that the random variable Y := P (A | G) is G-measurable.
Let F := 2Ω (the power set of Ω), and let H := {∅,Ω}.
(b). Is Y F-measurable? Why?
(c). Is Y H-measurable? Why?
(It is an intro to math finance course problem)

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

6.5

step-by-step explanation:

you said it was in the question

~courtney

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3