HELP PLEASE!!! Assume that when adults with smartphones are randomly selected, 59 % use them in meetings or classes. If 15 adult smartphone users are randomly selected, find the probability that exactly 10 of them use their smartphones in meetings or classes.
The probability is ?

5/10

Step-by-step explanation:

Let X will be the number of adults with smartphone which use them in meetings or classes.

X~Binomial(15, 0.59)

P(X=x) = C^{15}_x(0.59)^x(1-0.59)^{15-x}P(X=x)=C

x

15

(0.59)

x

(1−0.59)

15−x

You have to find the probability that exactly 10 of them use their smartphones in meetings or classes.

P(X=10) = C^{15}_{10} (0.59)^{10} (1-0.59)^{15-10} \\ = \frac{15!}{10!(15-10)!}(0.59)^{10}(0.41)^5 \\ = 3003 \times 0.00511 \times 0.01158 \\ = 0.17782P(X=10)=C

10

15

(0.59)

10

(1−0.59)

15−10

=

10!(15−10)!

15!

(0.59)

10

(0.41)

5

=3003×0.00511×0.01158

=0.17782

P=0.17782

hi!

i believe that john has 55 pieces of candy left.

!

i think it's either c or d

step-by-step explanation: the entire question is extremely odd. 04 obviously refers to the interest rate. honestly i will say the answer is c. because the (2 x 12) part would mean it's compounded semiannually. i'll say choose c.