Can someone Explain Pythagorean theorem, Exponents, Bedmas, Mean, Median, Mode, Range, Area and Perimeter in simple words

Pythagorean Theorem: C²= a²+b²    

a²+b²=c²

C is the longest line of a right angled triangle and a and b are the other two. If you have "a" and "c", but need to find b. You need to sqaure a and then subtract that from c². Then you have b

An Exponent is any example of ². When a small number is above another number. You multiple the "original" number x amount of time. Ex. 3³ 3*3*3

Bedmas is another way of saying "order of operation". Its the order that you calculate functions. It is calculated in this order:  Brackets, Exponents, Division/Multiplication, Addition/Subtraction.

I attached an example of Mean, Median, Mode, and Range.

Area: Area is the total space that a 2D object covers. And to calculate it we have to multiply the length of two sides that share a corner. For example, if we have a rectangle that the length of one side is equal to 3cm and the second side is equal to 5cm. Then we multiply them together to get the area. 3*5=15

Perimeter: The perimeter is the "outline" of a 2D shape. To calculate the perimeter we have to add all the sides together.

mark branliest

step-by-step explanation:

.6 is 1/2 of 12

the answer is actually d. i just took the test

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.