The perimeter of the rectangular playing field is 290 yards. The length of the field is 8 yards less than double the width. How would you find the dimensions of the playing​ field?

Let width be x

Length=2x-8

We know

Length=2x-8=2(51)-8=102-8=96

Width=x=51

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb