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Mathematics, 22.09.2021 08:30 gavergan

The complex number 16 has the following roots calculated. 1st root (k = 0): 2 left-bracket cosine (StartFraction 0 pi Over 4 EndFraction) I sine (StartFraction 0 pi Over 4 EndFraction right-bracket 2nd root (k = 1): 2 left-bracket cosine (StartFraction 2 pi Over 4 EndFraction) I sine (StartFraction 2 pi Over 4 EndFraction right-bracket 3rd root (k = 2): 2 left-bracket cosine (StartFraction 4 pi Over 4 EndFraction) I sine (StartFraction 4 pi Over 4 EndFraction right-bracket

What is the 4th root (k = 3) of 16?

the answer is b im just adding this for others to find

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