A stadium has 54,000 seats. Seats sell for $25 in Section A, $20 in Section B, and $15 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in $1,151,000 from each sold-out event. How many seats does each section hold?

Section A = $27,000Section B = $14,800Section C = $12,200

Step-by-step explanation:

A: 27000 seats, B: 14200 seats, C: 12800 seats

Step-by-step explanation:

A + B + C = 54000

B + C = A

=> 2A = 54000 => A = 27000

=> B + C = 27000 => C = 27000 - B

25A + 20B + 15C = 1151000

25x27000 + 20B + 15(27000 - B) = 1151000

=> B = 14200

=> C = 27000 - 14200 = 12800

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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step-by-step explanation: