Given the following: f(x) = 24 – 3x3 – 2x + 1; g(x) = 22 + 1; and
h(x) = x + 2.
What is the result of the following: (*) (2)
O 22 – 3x – 1+ 2; where x + +1
o 22 + 3x – 5+ *; where x + £1
0 2² – 3x +1+1; where x + +1
0 22 – 3x – 1+1; where x + +1

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof

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there are no choices to this, can you give us some choices so that i can answer it

step-by-step explanation: