F(c) = 1/x+5 -1 find the inverse function of f(x) and it’s domain

f ( x ) = 1/x+5 - 1

y = 1/x+5 - 1

Add both sides 1

y + 1 = 1/x+5 - 1 + 1

y + 1 = 1/x+5

Multiply both sides by ( x + 5 )

( x + 5 ) × ( y + 1 ) = ( x + 5 ) × 1 / x + 5

xy + x + 5y + 5 = 1

x( y + 1 ) + 5y + 5 = 1

Subtract both sides 5

x( y + 1 ) + 5y + 5 - 5 = 1 - 5

x( y + 1 ) + 5y = - 4

Subtract both sides 5y

x( y + 1 ) + 5y - 5y = - 4 - 5y

x( y + 1 ) = - 5y - 4

Divide both sides by ( y + 1 )

x( y + 1 ) ÷ ( y + 1 ) = ( - 5y - 4 ) ÷ ( y + 1 )

x = - 5y - 4 / y + 1

Thus the inverse function of f(x) is :

y = - 5x - 4 / x + 1 ( D : R - { - 1 } )

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

step-by-step explanation: