The data represent the number of cans collected by different classes for a service project.

12 14 22 14 18 23 42 13
9 19 22 14

a. Find the mean.
b. Find the median.
c. Eliminate the greatest value, 42, from the data set. Explain how the measures of
center change.

mean is 18.5 (add all values ÷ total number of values)

median is 16( arrange scores in ascending order and start removing scores from both the sides, 2 scores and up in the middle which were 14,18 add them and divide by 2)

omission of 42 will make the median 14(I'm not sure about this answer)

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}