Find the angle measures of a triangle if the first angle is thirty-one degrees more than the second, and the third is five degrees less than twice the first. Show the equation as well as the complete answer. (Hint: The sum of the interior angles of a triangle is 180 degrees)

23°, 54°, 103°

Step-by-step explanation:

let the2nd angle = x

1st angle = x + 31

3rd angle = 2(x + 31) - 5 = 2x + 62 - 5 = 2x + 57

Sum the 3 angles and equate to 180

x + 31 + x + 2x + 57 = 180 , that is

4x + 88 = 180 ( subtract 88 from both sides )

4x = 92 ( divide both sides by 4 )

x = 23

Then

1st angle = x + 31 = 23 + 31 = 54°

2nd angle = x = 23°

3rd angle = 2x + 57 = 2(23) + 57 = 46 + 57 = 103°

u rich

step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this