If the perimeter of the following figure is 58 meters find x. (6x + 10) meters
(-2x - 5)meters
(x + 3) meters

x = 10

Step-by-step explanation:

Sum the 3 sides and equate to 58

6x + 10 + x + 3 - 2x - 5 = 58 , that is

5x + 8 = 58 ( subtract 8 from both sides )

5x = 50 ( divide both sides by 5 )

x = 10

x = 10

Step-by-step explanation:

(6x+10)+(-2x-5)+(x+3) = 58

5x+8 = 58

5x = 58-8

x = 50/5

x = 10

its an acute right triangle

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240