Shown above is the graph of the differentiable function f, along with the line tangent to the graph of f at x=2. What is the value of f′(2) ?

f'(2) means "the slope of the tangent line to y=f(x) when x=2".

Since that tangent line is drawn, this is really asking, "What's the slope of that line?"

So, what's the rise/run for that line?

0.50 , 0.75

step-by-step explanation:

soo this can be solve by using the formula:

f = p( 1 + i)^ n

where f is the future profit

p is the initial profit

i is the percent increase

n is the number of years

a . f = 30000 ( 1.05)^n

b. f = 30000 ( 1.05)^15

f = $62,368