Find the x-intercepts of the parabola with vertex (4,-1) and y-intercept (0,15).
Write your answer in this form: (X1,41), (X2,42).
If necessary, round to the nearest hundredth.

9514 1404 393

  (3, 0), (5, 0)

Step-by-step explanation:

The vertex form of the equation for a parabola is ...

  y = a(x -h)^2 +k

where the vertex is (h, k) and the vertical scale factor is 'a'. The y-intercept is ...

  ah^2 +k = y-intercept

  a = ((y-intercept) -k)/h^2 = (15 -(-1))/4^2 = 1

So, the equation is ...

  y = (x -4)^2 -1 . . . . . vertex form with all the parameters filled in

The is zero when ...

  0 = (x -4)^2 -1

  (x -4)^2 = 1 . . . . add 1

  x -4 = ±√1 . . . . . square root

  x = 4 ± 1 . . . . . x-intercepts

The x-intercepts of the parabola are (3, 0) and (5, 0).

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6