Subtract the sum of
(8a-6a²+9) and (-10a-8+8a²) from 3

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-2a² + 2a + 2

Step-by-step explanation:

Given worded expression

subtract the sum of  (8a-6a²+9) and (-10a-8+8a²) from 3

Convert to numerical expression

3 - [(8a - 6a² + 9) + (-10a - 8 + 8a²)]

Expand parentheses in the bracket

=3 - [8a - 6a² + 9 - 10a - 8 + 8a²]

Combine like terms in the bracket

=3 - [(-6a² + 8a²) + (8a - 10a) + (9 - 8)]

=3 - [2a² - 2a + 1]

Expand bracket

=3 - 2a² + 2a - 1

Combine like terms

=-2a² + 2a + (3 - 1)

=

Hope this helps!! :)

Please let me know if you have any questions

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq