Find the measure of angles 1-7 given that lines m and n are parallel and t is transversal.

well here you go

1= 129

2= 51

3= 129

4= 51

5= 129

6= 51

7= 129

Step-by-step explanation:

since angle 51 is congruent to angle 2, they have the same measure which is 51. and if you look at it, angle 1+ 51 = 180 because they are supplementary angles. when you subtract 51 from 180 you get 129. for the other angles, look at the four on the bottom right side as a copy and paste of the four on the top left. basically meaning since 51 is congruent to angle 2 apply that same thing to angles 4 and 6. and since angle 1 is 129, that means angle 3 is 129 also. again, apply that same thing to angles 5 and 7.

sorry if its confusing, i get it

hope i helped :)

is this part of a question or something

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation