1. Write the number in standard form. 7.1 times 10 superscript 4 baseline (1 point) 710 7,100 71,000 710,000 2. Write the number in standard form. 5.01 times 10 superscript negative 3 baseline (1 point) 5,010 0.501 0.0501 0.00501 3. Select all of the numbers that are correctly written in scientific notation. (2 points) 42 times 10 superscript 5 baseline 1.1 times 10 superscript 4 baseline 7.0 times 20 superscript 4 baseline 6.01 times 10 superscript negative 4 baseline 18 point 0 time 10 cubed 4. Multiply. (2 point 0 times 10 superscript 4 baseline )(3 point 0 times 10 cubed )equals question mark. (1 point) 6.0 times 10 superscript 7 baseline 6.0 times 10 superscript 12 baseline 6.0 times 10 superscript 5 baseline 6.0 times 10 superscript 43 baseline 5. Add. Left Parenthesis 7.0 times 10 superscript 6 baseline Right Parenthesis plus Left Parenthesis 2.0 times 10 superscript 6 baseline Right Parenthesis equals question mark. (1 point) 9.0 times 10 superscript 4 baseline 9.0 times 10 superscript 12 baseline 9.0 times 10 superscript 6 baseline 9.0 times 10 superscript 10 baseline

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

should have been evaluated with one odd value and one even value. the expressions have equivalent values when . when , the first expression has a value of 3 and the second

step-by-step explanation:

h * s * a

h = history teacher

s = science teacher

a =   art teacher.

i see no data table, but just multiply the number of history teachers, science teachers, and art teachers.