ABCD is a parallelogram with diagonals AC and BC intersecting O Prove that triangle AOB is congruent to triangle DOC

Given: ABCD is a parallelogram with diagonals AC and BD intersecting at O.

To prove: ∆AOB ≅ ∆DOC

Proof: Since ABCD is a parallelogram.

Therefore, AB || CD and AB = CD, AD || BC and AD = BC

Now, AB || CD and transversal AC intersects them a A and C respectively.

Therefore, Angle BAC = Angle DCA [Since alternate interior angles are equal]

or, Angle BAO = Angle DCO

Now, in ∆AOB and ∆DOC,

Angle BAO = Angle DCO [proved above]

AB = CD [opposite sides of a parallelogram are equal]

Angle AOB = Angle COD [vertically opposite angles are equal]

So, by ASA congruency,

∆AOB ≅ ∆DOC.

idk

step-by-step explanation:

45.36 feet per second.

step-by-step explanation:

to find the most accurate determination for the number of feet per second tyrone traveled on his way to work let us convert miles to feet and minutes to seconds.

1 mile = 5280 feet.

1 minute = 60 seconds.

now we will divide 158400 by 3492 to find the most accurate determination for the number of feet per second tyrone traveled on his way to work.

therefore, tyrone traveled on his way to work at the rate of 45.36 feet per second.