Let A(1,13) and B (6,11) be two points. Find the slop of the line which passes through M(5,8) and is perpendicular to the line AB

5/2

Step-by-step explanation:

First, we need to find the slope of AB. To do that, I will use the equation

y2 - y1/x2 - x1

Plug in the coordinates.

11 - 13/6 - 1

Simplify.

-2/5

Our slope for line AB is -2/5. Now we can find the slope that is perpendicular to it that passes through the point (5, 8).

To do that, just take the slope from AB and make it an opposite value and reciprocal.

Our slope is 5/2.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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