The sum of 4 consecutive integers is 110. Find the integers.

26, 27, 28, 29

Step-by-step explanation:

Let the first integer be x.

Then, (x)+(x+1)+(x+2)+(x+3) = 110

=> x+x+1+x+2+x+3 = 110

=> 4x+6 = 110

=> 4x = 110-6

=> 4x = 104

=> x = 104/4

=> x = 26

So, the four consecutive integers are:

1. x = 26

2. x+1 = 26+1 = 27

3. x+2 = 26+2 = 28

4. x+3 = 26+3 = 29

x + (x+1) + (x+2) + (x+3) = 110

4x + 6 = 110

4x = 104

x = 26

26,27,28,29

Step-by-step explanation:

step-by-step explanation:

0

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.