Find the midpoint of A and B where A has coordinates (-5,3) and B has coordinates (3, -1)

Let me first tell u to how find the midnumber of two integers , look :

The midnumber of 3 and - 5 is finding like this :

( 3 + ( -5) ) ÷ 2 =

( 3 - 5 ) ÷ 2 =

- 2 ÷ 2 = - 1

Thus the midnumber of -5 & 3 is - 1 ;

Got it ?

This is what we do exactly to find the coordinates of the midpoint of two points.

As we have :

A = ( - 5 , 3 )

B = ( 3 , - 1 )

Midpoint of A & B = ( [ -5 + 3] ÷ 2 , [ 3 - 1 ] ÷ 2 )

Mp of A & B = ( -2 ÷ 2 , 2 ÷ 2 )

Mp of A & B = ( - 1 , 1 )

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752