2x -y +z = 7
2x + 4y - 2z = 0
x-y + 3z = 2

x = 3

y = -2

z = -1.

Step-by-step explanation:

2x -y +z = 7

2x + 4y - 2z = 0

x-y + 3z = 2

Subtracting the second equation from the first:

-5y + 3z = 7  (A)

Multiply the third equation by -2 and adding this to the second equation:

6y -8z = -4 (B)

Multiply A by 8 and B by 3, we get

-40y + 24z = 56

18y - 24z = -12       Adding:

-22y = 44

y = -2

So substituting for y in A:

-5(-2) + 3z = 7

3z = 7-10 = -3

z = -1.

Finally, substituting for y and z in the first equation:

2x -(-2) + (-1) = 7

2x + 2 - 1 = 7

2x = 7 - 1 = 6

x = 3.

x^5/3y^1/3 the correct answer

hope it

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.