If an airplane passes directly over your head at an altitude of 12 kilometers, how far is the airplane from your position after it has flown 16 kilometers farther at the same altitude?

20 kilometres

Step-by-step explanation:

We will imagine a triangle. The hypotenuse of the triangle is the distance between you and the plane. 16 kilometres is the aerial space between you two, in other words its the base of the triangle. 12 km is the length of the third leg of the triangle. We will apply the pythagorean theorem to find the length of the hypotenuse and the distance between you and the plane.

a^2 + b^2 = c^2

12^2 + 16^2 = c^2

144 + 256 = c^2

400 = c^2

square root of 400 is c which equals 20 km.

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

idk

step-by-step explanation: