19) Write the slope-intercept form of the equation of the line described by (-4,-5), parallel to y = -2x - 5.

Step-by-step explanation:

Since is it parallel to the given line, we can directly take the slope from the given equation.

m = -2 according to the given equation.

Next, use the point (-4,-5) to write the point-slope form first.

y-(-5) = -2(x-(-4))

Then use basic algebra to put it into slope-intercept form, which is y = mx + b.

y + 5 = -2x - 8

y = -2x - 13

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this