16. How many liters of a 60% alcohol solution must be added to 60 liters of a 30% alcohol solution to produce a 40% alcohol solution?
Quantity
Product
Percent
or
rate
Item 1
Item2
Combine
d Item

Step-by-step explanation:

Step 1: Question statement and Inferences

Let x liters of the 60% solution be added.

So, amount of Alcohol in this solution = 60% of x = 0.6x L

Now, let us consider the 40% solution.

The total volume of this solution is 50 L

So, amount of Alcohol in this solution = 40% of 50

 

Step 2: Finding required values

When x L of 60% solution are mixed with 50 L of the 40% solution, the total volume of the resultant solution will be (50+x) L

By the Law of Conservation of Mass,

Amount of alcohol in the input solutions = Amount of alcohol in the final solution

=> Amount of alcohol in the final solution = 20 + 0.6x

So, concentration of Alcohol in the final solution



Step 3: Calculating the final answer

It is given that the concentration of alcohol in the final solution is 50%



the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation:

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

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